A) \[B{{r}_{2}},KBr{{O}_{3}}\]
B) \[C{{l}_{2}},KCl{{O}_{3}}\]
C) \[{{I}_{2}},NaI{{O}_{3}}\]
D) \[C{{l}_{2}},NaCl{{O}_{3}}\]
Correct Answer: B
Solution :
A halate will be formed from halogen and the greenish yellow gas is\[C{{l}_{2}}\]. The halate which is used in fire works and safety match is\[KCl{{O}_{3}}\]. The reaction involved is \[\underset{\begin{smallmatrix} Greenish \\ yellow\text{ }gas \end{smallmatrix}}{\mathop{3C{{l}_{2}}}}\,+6KOH\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,Halate \\ (Potassium\text{ }charred) \end{smallmatrix}}{\mathop{KCl{{O}_{3}}}}\,+5KCl+3{{H}_{2}}O\]
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