A) \[\frac{1}{\sqrt{3}}T\]
B) \[T\]
C) \[2T\]
D) \[\frac{2}{\sqrt{3}}T\]
Correct Answer: D
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\] So, \[T\propto \frac{1}{\sqrt{g}}\] \[\Rightarrow \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{g}_{2}}}{{{g}_{1}}}}\] Here, \[{{T}_{1}}=T\] \[{{g}_{1}}=g+\frac{g}{3}=\frac{4}{3}g\] \[{{g}_{2}}=g,{{T}_{2}}=?\] \[{{T}_{2}}={{T}_{1}}\sqrt{\frac{{{g}_{1}}}{{{g}_{2}}}}=T\sqrt{\frac{4}{\frac{3}{g}}g}=\frac{2}{\sqrt{3}}T\]
You need to login to perform this action.
You will be redirected in
3 sec
