A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{3}{4}\]
D) \[\frac{3}{2}\]
Correct Answer: A
Solution :
For, an organ pipe open at one end, Frequency of 2nd hormonic or first overtone \[={{n}_{1}}=\frac{3v}{4{{l}_{1}}}\] For the organ pipe open at both the ends, Frequency of 2nd overtone or third harmonic \[={{n}_{2}}=\frac{3v}{2{{l}_{2}}}\] Since, \[{{n}_{1}}={{n}_{2}}\] So \[\frac{3v}{4{{l}_{1}}}=\frac{3v}{2{{l}_{2}}}\Rightarrow \frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
