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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    Three resistances of\[2\,\Omega ,3\,\Omega \].and\[6\,\Omega \]are connected in parallel and the combination is connected in series with 2 V battery having internal resistance of\[1\,\Omega \]. The current in the battery is

    A)  1A                                         

    B)  3A

    C)  2A                                         

    D)  4A

    Correct Answer: A

    Solution :

                    The effective resistance of the combination is \[\frac{1}{{{R}_{p}}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3+2+1}{6}=1\] \[\Rightarrow \]               \[{{R}_{p}}=1\,\Omega \] Total resistance of the circuit                 \[=R={{R}_{p}}+r=1+1=2\,\Omega \] So, battery current is \[i=\frac{V}{R}=\frac{2}{2}=1A\]


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