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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    At\[90{}^\circ C,\]pure water has\[[{{H}^{+}}]={{10}^{-6}}M,\]if 100 mL of\[0.2\text{ }M\text{ }HCl\]is added to 200mL of 0.1 M KOH at\[90{}^\circ C\]then pH of the resulting solution will be

    A)  5                            

    B)  6      

    C)  7                            

    D)  4

    Correct Answer: B

    Solution :

                    20 meq. of\[HCl\]reacts completely with 20 meq. Of KOH Therefore, the final solution is neutral. Thus, at\[90{}^\circ C\].\[(pH=\log {{H}^{+}})\]hence. \[pH=6\].


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