A) 80 mL of \[{{O}_{2}}\]
B) 60 mL of \[{{O}_{2}}\]
C) 80 mL of \[C{{O}_{2}}\]
D) 60 mL of\[C{{O}_{2}}\]
Correct Answer: A
Solution :
\[\underset{40\,mL}{\mathop{CO}}\,+\underset{20\,mL}{\mathop{\frac{1}{2}{{O}_{2}}}}\,\xrightarrow[{}]{{}}\underset{\underset{Absorbed}{\mathop{\downarrow KOH}}\,}{\mathop{\underset{40\,mL}{\mathop{C{{O}_{2}}}}\,}}\,\] Volume of \[{{O}_{2}}\]left\[=(100-20)=80\text{ }mL\]
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