A) 2.74 W
B) 0.43 W
C) 0.79 W
D) 1.13 W
Correct Answer: C
Solution :
[c]| \[{{\text{P}}_{\text{av}}}\text{=}{{\left( \frac{{{\text{V}}_{\text{RMS}}}}{\text{Z}} \right)}^{\text{2}}}\text{R}\] |
| \[\text{Z=}\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}=56\Omega \] |
| \[\therefore {{P}_{av}}={{\left( \frac{10}{\left( \sqrt{2} \right)56} \right)}^{2}}\times 50=0.79\,\,\text{W}\] |
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