NEET Physics Alternating Current / प्रत्यावर्ती धारा NEET PYQ-Alternating Current

  • question_answer
    A coil of inductive reactance \[31\,\,\Omega \] has a resistance of \[8\,\,\Omega \]. It is placed in series with a condenser of capacitative reactance \[25\,\,\Omega \]. The combination is connected to an a.c. soruce of 110 V. The power factor of the circuit is:                                                                                                          [AIPMT (S) 2006]

    A)  0.56              

    B)   0.64   

    C)  0.80    

    D) 0.33

    Correct Answer: C

    Solution :

    Key Idea: Power factor \[(\cos \phi )\] is a ratio of resistance and impedance of AC circuit. Power factor of AC circuit is given by
                \[\cos \phi =\frac{R}{Z}\]                                    …(i)
    where R is resistance employed and Z the impedance of the circuit.
    \[Z=\sqrt{{{R}^{2}}+({{X}_{L}}+X_{C}^{2})}\]                  ...(ii)
    Eqs. (i) and (ii) meet to give,
    \[\cos \phi =\frac{R}{\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}}\]    …(iii)
    Given,   \[R=8\Omega ,\,\,{{X}_{L}}=31\,\Omega ,\,\,{{X}_{C}}=25\,\Omega \]
    \[\therefore \]      \[\cos \phi =\frac{8}{\sqrt{{{(8)}^{2}}+{{(31-25)}^{2}}}}\]
    \[=\frac{8}{\sqrt{64+36}}\]
    Hence,  \[\cos \,\phi =0.80\]


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