A) \[\frac{5}{27}\]
B) \[\frac{3}{23}\]
C) \[\frac{7}{29}\]
D) \[\frac{9}{31}\]
Correct Answer: A
Solution :
| Wavelength for Lyman series |
| \[{{\lambda }_{L}}=\frac{1}{R\left( 1-\frac{1}{4} \right)}=\frac{4}{3R}\] |
| And wavelength for Balmer series |
| \[{{\lambda }_{L}}=\frac{1}{R\left( \frac{1}{4}-\frac{1}{9} \right)}=\frac{1}{R\left( \frac{5}{36} \right)}=\frac{36}{5R}\] |
| \[\therefore \] \[\frac{{{\lambda }_{L}}}{{{\lambda }_{B}}}=\frac{4}{3R}\times \frac{5R}{36}=\frac{5}{27}\] |
| \[\Rightarrow \] \[{{\lambda }_{L}}:{{\lambda }_{B}}=5:27\] |
You need to login to perform this action.
You will be redirected in
3 sec
