NEET Physics Atomic Physics NEET PYQ-Atomic Physics

  • question_answer
    Given the value of Rydberg constant is \[{{10}^{7}}{{m}^{-1}},\] the wave number of the last line of the Balmer series in hydrogen spectrum will be :-                                                                     [NEET - 2016]

    A)  \[0.025\times {{10}^{4}}\text{ }{{m}^{1}}\]

    B)       \[0.5\times {{10}^{7}}\text{ }{{m}^{1}}\]

    C)  \[0.25\times {{10}^{7}}\text{ }{{m}^{1}}\]

    D)       \[2.5\times {{10}^{7}}\text{ }{{m}^{1}}\]

    Correct Answer: C

    Solution :

    [c] \[\frac{1}{\lambda }=R{{Z}^{2}}\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)={{10}^{7}}\times {{1}^{2}}\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{\infty }^{2}}} \right)\]
                \[\Rightarrow \] wave number \[=\frac{1}{\lambda }=0.25\times {{10}^{7}}{{m}^{-1}}\]


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