A) sodium ethoxide
B) ethyl chloride
C) dry \[HCl-{{C}_{2}}{{H}_{s}}OH\]
D) ethanol
Correct Answer: D
Solution :
| [d] Ethyl benzoate is prepared by reacting benzoic acid and ethanol in presence of dry HCl. This reaction is known as esterification reaction. |
| \[\underset{Benzoic\,acid}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,+\underset{Ethanol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{Dry}{\mathop{\xrightarrow{HCl}}}\,\]\[\underset{Ethyl\,\,benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}+{{H}_{2}}O}}\,\] |
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