question_answer

In a set of the given reactions, acetic acid yielded a product C,

\[C{{H}_{3}}COOH+PC{{l}_{5}}\to A\xrightarrow[Anh.\,AlC{{l}_{3}}]{{{C}_{6}}{{H}_{6}}}\]\[B\underset{Ether}{\mathop{\xrightarrow{{{C}_{2}}{{H}_{5}}MgBr}}}\,C\] product C would be :                  [AIPMT 2003]

A)       \[C{{H}_{3}}CH(OH){{C}_{6}}{{H}_{5}}\]    

B) \[C{{H}_{3}}-\overset{\begin{smallmatrix}  {{C}_{2}}{{H}_{5}} \\  | \end{smallmatrix}}{\mathop{C(OH){{C}_{6}}{{H}_{5}}}}\,\]

C) \[C{{H}_{3}}CH(OH){{C}_{2}}{{H}_{5}}\]

D) \[C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\]

Correct Answer: B

Solution :

[b] \[C{{H}_{3}}COOH+PC{{l}_{5}}\xrightarrow[{}]{{}}C{{H}_{3}}\underset{(A)}{\mathop{COCl}}\,\]