A) \[I{{F}_{3}},Xe{{F}_{2}}\]
B) \[BeC{{l}_{2}},Xe{{F}_{2}}\]
C) \[Te{{l}_{2}},Xe{{F}_{2}}\]
D) \[IBr_{2}^{-},Xe{{F}_{2}}\]
Correct Answer: D
Solution :
[d]\[IBr_{2}^{-},\,Xe{{F}_{2}}\] Total number of valence electrons are equal in both the species and the species are linear also.
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