A) NO
B) \[N_{2}^{+}\]
C) CO
D) \[O_{2}^{-}\]
Correct Answer: C
Solution :
| Paramagnetic character is shown by those atoms or molecules which have unpaired electrons. |
| In the given compounds CO is not paramagnetic since it does not have unpaired electrons. The configuration of CO molecule is |
| \[CO(14)=\sigma 1{{s}^{2}},\,\sigma *\,1{{s}^{2}},\,\sigma 2{{s}^{2}},\,\sigma *\,2{{s}^{2}},\,\sigma 2p_{x}^{2},\] |
| \[\pi 2p_{y}^{2},\,\pi 2p_{z}^{2}\] |
You need to login to perform this action.
You will be redirected in
3 sec
