question_answer

Reaction \[Ba{{O}_{2}}(s)~BaO(s)+{{O}_{2}}(g),~\]

\[\Delta H=+ve\]. In equilibrium condition, Pressure of \[{{O}_{2}}\] depends on:              [AIPMT 2002]

A)  increased mass of \[Ba{{O}_{2}}\]                 

B)             increased mass of BaO

C) increased temperature of equilibrium.

D)       increased mass of \[Ba{{O}_{2}}\] and BaO both

Correct Answer: C

Solution :

According to law or mass action.

The rate of forward reaction

or

But concentration of solid = 1

then,

Similarly the rate of backward reaction

or

Conc. Of

or

At equilibrium

or

where  Partial pressure of

or          (Equilibrium constant)

or

So, from the above it is clear that pressure of does not depend upon Cone, of reactants. The given equation is an endothermic reaction. If the temperature of such reaction is increased then dissociation of  would increase; and more  is produced.