A) 1000 K
B) \[\frac{2000}{2.303}K\]
C) 2000K
D) \[\frac{1000}{2.303}K\]
Correct Answer: D
Solution :
| [d] Key Idea: The Arrhenius equation is represented as\[k=A{{e}^{-{{E}_{a}}/RT}}\] |
| In the given equations, first take log and. Then compare them. |
| \[{{k}_{1}}={{10}^{16}}{{e}^{-2000/T}}\] |
| \[{{k}_{2}}={{10}^{15}}{{e}^{-1000/T}}\]On taking log, we get |
| \[\log {{k}_{1}}=\log {{10}^{16}}-\frac{2000}{2.303T}\] (i) |
| \[\log {{k}_{2}}=\log {{10}^{15}}-\frac{1000}{2.303T}\] (ii) |
| \[\because \]\[{{k}_{1}}={{k}_{2}}\]Hence, from Eqs. (i) and (ii) \[T=\frac{1000}{2.303}K\] |
You need to login to perform this action.
You will be redirected in
3 sec
