NEET Chemistry NEET PYQ-Chemical Kinetics

For the reactions \[2{{N}_{2}}{{O}_{5}}\to 4N{{O}_{2}}+{{O}_{2}}\] rate and rate constant are \[1.02\times {{10}^{-4}}\] and \[3.4\times {{10}^{-5}}\,{{s}^{-1}}\] respectively, then cone, of \[{{N}_{2}}{{O}_{5}}\] at that time will be: [AIPMT 2001]

A) 1.732

B) 3

C) \[1.02\times {{10}^{-4}}\]

D) \[3.4\times {{10}^{5}}\]

Correct Answer: B

Solution :

[b] \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\]

\[\frac{-d[{{N}_{2}}{{O}_{5}}]}{dt}=k\,[{{N}_{2}}{{O}_{5}}]\]

\[1.02\times {{10}^{-4}}=3.4\times {{10}^{-5}}\,{{s}^{-1}}\times \,[{{N}_{2}}{{O}_{5}}]\]

\[\therefore \] \[[{{N}_{2}}{{O}_{5}}]=\frac{1.02\times {{10}^{-4}}}{3.4\times {{10}^{-5}}}=3\]