NEET Chemistry NEET PYQ-Coordination Chemistry

  • question_answer
    In an octahedral structure, the pair of dorbitals involved in \[{{d}^{2}}s{{p}^{3}}\]hybridisation is: [AIPMT (S) 2004]

    A) \[{{d}_{{{x}^{2}}-{{y}^{2}}}}{{d}_{{{z}^{2}}}}\]

    B) \[{{d}_{xz}},{{d}_{{{x}^{2}}-{{y}^{2}}}}\]

    C) \[{{d}_{{{z}^{2}}'}}{{d}_{xz}}\]

    D) \[{{d}_{xy}},{{d}_{yz}}\]

    Correct Answer: C

    Solution :

    [c] In the formation of\[{{d}^{2}}s{{p}^{3}}\]hybrid orbitals, two\[(n-1)d\] orbitals of \[{{e}_{g}}\]set i.e., \[(n-1)\]\[{{d}_{{{z}^{2}}}}\]and \[(n-1){{d}_{{{x}^{2}}-{{y}^{2}}}}\]orbitals, one ns and three np\[(n{{p}_{x}}n{{p}_{y}}\,\,and\,\,n{{p}_{z}})\] orbitals combine together and form six \[{{d}^{2}}s{{p}^{3}}\] hybrid orbitals.


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