question_answer

Number of possible isomers for the complex \[[Co{{(en)}_{2}}C{{l}_{2}}]Cl\] will be (en = ethylenediamine) [NEET 2015 (Re)]

A) 2

B) 1                     

C) 3

D) 4

Correct Answer: C

Solution :

[c] \[[Co{{(en)}_{2}}C{{l}_{2}}]Cl\]

Possible isomers are

Hence, total number of Stereoisomers = 2 + 1 = 3