A) \[{{T}_{n}}=\frac{{{T}_{i}}}{2}\]
B) \[{{T}_{n}}=2{{T}_{i}}\]
C) \[{{T}_{n}}={{T}_{i}}-T\]
D) \[{{T}_{n}}={{T}_{i}}+T\]
Correct Answer: A
Solution :
| [a] It is found that temperature of inversion \[({{T}_{i}})\] is as much above the neutral temperature \[({{T}_{n}})\] as neutral temperature is above the temperature of the cold junction (T), i. e., |
| \[{{T}_{i}}-{{T}_{n}}={{T}_{n}}-T\] |
| or \[{{T}_{i}}=2{{T}_{n}}-T\] |
| But, here the cold junction is kept at \[0{}^\circ C,\] hence |
| \[T=0\]. |
| Thus, \[{{T}_{i}}=\text{ }2{{T}_{n}}\] |
| or \[{{T}_{n}}=\frac{{{T}_{i}}}{2}\] |
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