| The total power dissipated in watts in the circuit shown here [AIPMT (S) 2007] |
 |
A) 16
B) 40
C) 54
D) 4
Correct Answer: C
Solution :
| [c] The resistances of \[6\,\,\Omega \] and \[3\,\,\Omega \] are in parallel in the given circuit, their equivalent resistance is |
| \[\frac{1}{{{R}_{1}}}=\frac{1}{6}+\frac{1}{3}=\frac{1+2}{6}=\frac{1}{2}\] |
| or \[{{R}_{1}}=2\,\Omega \] |
| Again, R, is in series with \[4\,\,\Omega \] resistance, hence |
| \[R={{R}_{1}}+4=2+4=6\,\Omega \] |
| Thus, the total power dissipated in the circuit |
| Here, \[V=18V,\,\,R=6\,\,\Omega \] |
| Thus, \[P=\frac{{{(18)}^{2}}}{6}=54\,W\] |
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