A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Correct Answer: D
Solution :
| [d] Key Idea: Apply first law of electrolysis during deposition of charge on an electrode through electrolysis. |
| If m is the mass of a substance deposited or liberated at an electrode during electrolysis when a charge q passes through electrolyte, then according to Faraday's first law of electrolysis. |
| \[m\,\propto \,\,q\] |
| or \[m=zq\] |
| where z is a constant of proportionality and is called electrochemical equivalent (ECE) of the substance. |
| If an electric current \[I\] flows through the electrolyte, then |
| \[q=it\] |
| \[\therefore \] \[m=zit\] |
| Here, mass of copper deposited on the electrode |
| \[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] |
| \[=27\times {{10}^{-2}}=0.27\,g\] |
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