A) \[0.2\,\,\Omega \]
B) \[0.5\,\,\Omega \]
C) \[0.8\,\,\Omega \]
D) \[1.0\,\,\Omega \]
Correct Answer: B
Solution :
[b] |
As \[l=\frac{E}{R+r}\] |
or \[E=l(R+r)\] |
\[2.1=0.2(10+r)\] |
\[10+r=\frac{2.1}{2}\times 10\] |
\[\therefore \] \[r=10.5-10=0.5\,\Omega \] |
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