A) 1.0 A
B) 0.2 A
C) 0.1 A
D) 2.0 A
Correct Answer: B
Solution :
[b] Effective resistance, |
\[{{R}_{eff}}=\frac{40\times 120}{120+40}=\frac{4800}{160}=30\,\Omega \] |
\[\therefore \] Current \[l=\frac{7}{(30+5)}=\frac{7}{35}=0.2A\] |
\[\left[ \because l=\frac{E}{R+r} \right]\] |
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