A) is zero
B) depends upon the choice of the two materials of the thermocouple
C) is negative
D) is positive
Correct Answer: A
Solution :
| [a] We have |
| \[e=at+b{{t}^{2}}\] |
| \[\frac{de}{dt}=a+2bt\] |
| Natural temperature \[{{T}_{n}}=-\frac{a}{2b}\] |
| At netural temperature \[\frac{de}{dt}=0\] |
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