| A millivolt meter of 25 mV range is to be converted into an ammeter of 25 A range. |
| [AIPMT (S) 2012] |
| The value (in ohm) of necessary shunt will be |
A) 0.001
B) 0.01
C) 1
D) 0.05
Correct Answer: A
Solution :
| [a] The full scale deflection current \[{{i}_{g}}=\frac{25\,mV}{G}\text{ampere}\] where G is the resistance of the meter. |
| The value of shunt required for converting it into ammeter of range 25 A is \[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\] |
| So that, \[S\approx \frac{25\,mV}{25}=0.001\,\Omega \] |
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