A) 3.6 A
B) 2.8 A
C) 2.5 A
D) 5.0 A
Correct Answer: D
Solution :
| Efficiency is defined as the ratio of output power and input power |
| i.e., \[\eta %=\frac{{{P}_{out}}}{{{P}_{in}}}\times 100=\frac{{{V}_{s}}{{i}_{s}}}{{{V}_{p}}{{i}_{p}}}\times 100\] |
| \[80=\frac{2\times 440}{220\times {{i}_{p}}}\times 100\] |
| \[\Rightarrow \] \[{{i}_{p}}=5A\] |
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