A) 1.389 H
B) 138.88 H
C) 0.138 H
D) 13.89 H
Correct Answer: D
Solution :
| [d] Energy stored in inductor |
| \[\text{U=}\frac{\text{1}}{\text{2}}\text{L}{{\text{l}}^{\text{2}}}\] |
| \[\text{25}\times \text{1}{{\text{0}}^{-3}}=\frac{1}{2}\times L\times {{(60\times {{10}^{-3}})}^{2}}\] |
| \[\text{L=}\frac{\text{25 }\!\!\times\!\!\text{ 2 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{6}}}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-3}}}}{\text{3600}}\] |
| \[\text{=}\frac{500}{36}\] |
| \[\text{= 13}\text{.89 H}\] |
You need to login to perform this action.
You will be redirected in
3 sec
