A) 5 s
B) 1/5 s
C) 40 s
D) 20 s
Correct Answer: A
Solution :
| Time constant of L-R circuit is, |
| \[\tau =\frac{L}{R}\] |
| Here, \[L=40H,\,\,R=8\,\,\Omega ,\,\,E=2V\] |
| \[\therefore \] \[\tau =\frac{40}{8}=5s\] |
| Note: At a time equal to one time constant the current has risen to \[\left( 1-\frac{1}{\theta } \right)\] or about 63% of its initial |
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