| Given, [AIPMT (S) 2009] |
| (i) \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Cu,\]\[{{E}^{o}}=0.337\,V\] |
| (ii) \[C{{u}^{2+}}+{{e}^{-}}\xrightarrow[{}]{{}}C{{u}^{+}},\]\[{{E}^{o}}=0.153\,V\] |
| Electrode potential, \[{{E}^{o}}\] for the reaction, \[Cu+{{e}^{-}}\xrightarrow[{}]{{}}Cu\], will be - |
A) 0.52 V
B) 0.90 V
C) 0.30 V
D) 0.38 V
Correct Answer: A
Solution :
| [a] Key Idea Gibb's free energy is an additive property. |
| \[\frac{d[N{{H}_{3}}]}{dt}=2\times {{10}^{-4}}\] |
| For reaction, \[{{L}^{-1}}{{s}^{-1}},\] |
| \[\frac{-d[{{H}_{2}}]}{dt}\] ...(i) |
| For reaction, \[3\times {{10}^{4}}\,mol\,{{L}^{-1}}\,{{s}^{-1}}\] |
| \[4\times {{10}^{4}}\,mol\,{{L}^{-1}}\,{{s}^{-1}}\] ...(ii) |
| Adding Eqs. (i) and (ii), we get |
| \[6\times {{10}^{4}}\,mol\,{{L}^{-1}}\,{{s}^{-1}}\]\[1\times {{10}^{4}}\,mol\,{{L}^{-1}}\,{{s}^{-1}}\] |
| \[[O{{H}^{-}}]\] |
| \[\text{Ba(OH}{{\text{)}}_{\text{2}}}\] |
| \[TiF_{6}^{2-},CoF_{6}^{3-},C{{u}_{2}}C{{l}_{2}}\]\[NiCl_{4}^{2-}\] |
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