| Consider the following relations for emf of a electrochemical cell [AIPMT (M) 2010] |
| [A] Emf of cell = (oxidation potential of anode) (reduction potential of cathode) |
| [B] Emf of cell = (oxidation potential of anode) + (reduction potential of cathode) |
| [C] Emf of cell = (reduction potential of anode) + (reduction potential of cathode) |
| [D] Emf of cell = (oxidation potential of anode)-(0xidation potential of cathode) |
| Which of the above relations are correct? |
A) and
B) and
C) and
D) None of these
Correct Answer: D
Solution :
| [d] \[{{E}_{cell}}={{E}^{o}}_{_{(red)}^{cathode}}-{{E}^{o}}_{_{(red)}^{anode}}\] |
| Or \[{{E}_{cell}}={{E}^{o}}_{_{(red)}^{cathode}}+{{E}^{o}}_{_{(oxid)}^{Anode}}\] |
| Or \[{{E}_{cell}}={{E}^{o}}_{_{(oxid)}^{anode}}-{{E}^{o}}_{_{(oxid)}^{cathode}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
