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NEET Chemistry NEET PYQ-Electrochemistry

  • question_answer
    Standard electrode potential for \[S{{n}^{4+}}/S{{n}^{2+}}\] couple is +0.15 V and that for the \[C{{r}^{3+}}/Cr\] couple is -0.74. These two couples in their standard state are connected to make a cell. The cell potential will be              [AIPMT (S) 2011]

    A) + 0.89 V

    B) + 0.18 V

    C) + 1.83 V

    D) + 1.199 V

    Correct Answer: A

    Solution :

    [a] \[E{{_{Sn}^{o}}_{^{4+}/S{{n}^{2+}}}}=+0.15\,\text{V}\]
    \[E{{_{Cr}^{o}}_{^{3+}/Cr}}=-\,0.74\,\text{V}\]
    \[E_{cell}^{o}={{E}^{o}}_{cathode(RP)}-{{E}^{o}}_{anode(RP)}\]
                \[=0.15-(-0.74)\]
                \[=+\,0.89\,V.\]


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