at infinite dilution of 
and 
are 126.4, 425.9 and 
respectively. 
for 
will be [AIPMT (M) 2012]
A)
B) \[180.5\,\,S\,\,c{{m}^{2}}\,mo{{l}^{-1}}\]
C) \[290.8\,\,S\,\,c{{m}^{2}}\,mo{{l}^{-1}}\]
D) \[390.5\,\,S\,\,c{{m}^{2}}\,mo{{l}^{-1}}\]
Correct Answer: D
Solution :
| [d] \[C{{H}_{3}}COONa+HCl\xrightarrow{{}}NaCl+C{{H}_{3}}COOH\] |
| \[91+425.9=126.4+x\] |
| \[\therefore \] \[x=516.9-126.4\] |
| \[=390.5\,\,S\,\,c{{m}^{2}}\,\,mo{{l}^{-1}}\] |
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