A) Oxygen gas
B) \[{{H}_{2}}S\] gas
C) \[S{{O}_{2}}\] gas
D) Hydrogen gas
Correct Answer: A
Solution :
| [a] During the electrolysis of dil. sulphuric acid using Pt electrodes following reaction will take place. |
| At cathode: \[4{{H}^{+}}(aq)+4{{e}^{-}}\xrightarrow{{}}2{{H}_{2}}(g)\] |
| At anode: \[2{{H}_{2}}O(l)\xrightarrow{{}}{{O}_{2}}(g)+4{{H}^{+}}(aq)+4{{e}^{-}}\] |
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