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  5. Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन

NEET Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन NEET PYQ-Fluid Mechanics, Surface Tension and Viscosity

  • question_answer
    A soap bubble, having radius of 1 mm, is blown from a detergent solution having a surface tension of \[2.5\times {{10}^{2}}\]N/m. The pressure inside the bubble equals at a point \[{{Z}_{0}}\]below the free surface of water in a container. Taking\[g=10\text{ }m/{{s}^{2}}\], density of water\[={{10}^{3}}kg/{{m}^{3}}\], the value of \[{{Z}_{0}}\] is:                                                                                                                          [NEET 2019]

    A)  1 cm   

    B)       0.5 cm

    C)  100 cm            

    D)       10 cm

    Correct Answer: A

    Solution :

    [a] \[\rho g{{Z}_{0}}=\frac{4T}{R}\]
    \[{{10}^{3}}.10.{{Z}_{0}}=\frac{4(2.5\times {{10}^{-2}})}{{{10}^{-3}}}\]
    \[=\frac{100}{{{10}^{4}}}\]
    \[{{Z}_{0}}={{10}^{-2}}\]
    \[Z=1cm\]


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