NEET Chemistry NEET PYQ-Haloalkanes and Haloarenes

  • question_answer
    Which one is most reactive towards \[{{S}_{N}}1\]reaction? [AIPMT (S) 2010]

    A) \[{{C}_{6}}{{H}_{5}}CH({{C}_{6}}{{H}_{5}})Br\]

    B) \[{{C}_{6}}{{H}_{5}}CH(C{{H}_{3}})Br\]

    C) \[{{C}_{6}}{{H}_{5}}C(C{{H}_{3}})({{C}_{6}}{{H}_{5}})Br\]

    D) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Br\]

    Correct Answer: C

    Solution :

    [c] Key Idea \[{{S}_{N}}1\] reaction involves the formation of carbonation intermediate. More the stability of carbonation, more is the reactivity of alkyl/aryl halides towards \[{{S}_{N}}1\] reaction.
    The intermediate carbonations formed by given halides are as:
    \[{{C}_{6}}{{H}_{5}}CH({{C}_{6}}{{H}_{5}})Br\xrightarrow[{}]{{}}{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{+}{\mathop{C}}\,H+B{{r}^{-}}\]
    \[{{C}_{6}}{{H}_{5}}CH(C{{H}_{3}})Br\xrightarrow[{}]{{}}{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,H(C{{H}_{3}})+B{{r}^{-}}\]\[{{C}_{6}}{{H}_{5}}C(C{{H}_{3}})({{C}_{6}}{{H}_{5}})Br\xrightarrow[{}]{{}}\]\[{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{+}{\mathop{C}}\,(C{{H}_{3}})+B{{r}^{-}}\]
    \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}Br\xrightarrow[{}]{{}}{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,{{H}_{2}}+B{{r}^{-}}\]
    The order of stability of these carbocations is as\[{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{+}{\mathop{C}}\,(C{{H}_{3}})>{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{+}{\mathop{C}}\,H\]\[>{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,H(C{{H}_{3}})>{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{C}}\,{{H}_{2}}\]
    Thus, \[{{C}_{6}}{{H}_{5}}C(C{{H}_{3}})({{C}_{6}}{{H}_{5}})Br\] is most reactive towards \[{{S}_{N}}1\] reaction.


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