A) \[B{{r}_{2}}<C{{l}_{2}}<{{F}_{2}}:\] Oxidising power
B) \[B{{r}_{2}}<C{{l}_{2}}<{{F}_{2}}:\] Electronegativity
C) \[B{{r}_{2}}<{{F}_{2}}<C{{l}_{2}}:\] Electron affinity
D) \[B{{r}_{2}}<C{{l}_{2}}<{{F}_{2}}:\] Bond energy
Correct Answer: D
Solution :
[d] Bond energy of \[{{F}_{2}},\text{ }C{{l}_{2}}\] and \[B{{r}_{2}}\] are 38, 57 and 45.5 kcal/mol respectively. So, the correct decreasing order of bond energy is \[C{{l}_{2}}>B{{r}_{2}}>{{F}_{2}}\]
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