A) \[2KI+B{{r}_{2}}3KBr+{{I}_{2~}}\]
B) \[2KBr+{{I}_{2}}2KI+B{{r}_{2}}\]
C) \[2KBr+C{{l}_{2}}2KCl+B{{r}_{2}}\]
D) \[2{{H}_{2}}O+2{{F}_{2}}~4HF+{{O}_{2}}\]
Correct Answer: B
Solution :
[b] \[2KBr+{{I}_{2}}\xrightarrow{{}}2KI+B{{r}_{2}}\] reaction is not possible because \[B{{r}^{-}}\] ion is not oxidised in \[B{{r}_{2}}\] with \[{{I}_{2}}\] due to higher electrode potential of \[{{I}_{2}}\] than bromine. In halogens fluorine can displace chlorine bromine and iodine, chlorine can displays bromine and iodine and bromide can display iodine from their salts.
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