A) \[2\times {{10}^{8}}M\]
B) \[1\times {{10}^{13}}M\]
C) \[1\times {{10}^{8}}M\]
D) \[2\times {{10}^{13}}M\]
Correct Answer: D
Solution :
[d] \[\underset{s}{\mathop{Ni{{(OH)}_{2}}}}\,\underset{s}{\mathop{N{{i}^{2+}}}}\,+\underset{2s}{\overset{\Theta }{\mathop{2OH}}}\,\] |
\[\underset{0.1}{\mathop{NaOH}}\,\xrightarrow{{}}\underset{0.1}{\mathop{N{{a}^{+}}}}\,+\underset{0.1}{\overset{\Theta }{\mathop{OH}}}\,\] |
Total \[[\overset{\Theta }{\mathop{OH}}\,]=2s+0.1\approx 0.1\] |
Ionic product \[=[N{{i}^{2+}}]{{[\overset{-}{\mathop{O}}\,H]}^{2}}\] |
\[2\times {{10}^{-15}}=s{{(0.1)}^{2}}\] |
\[s=2\times {{10}^{-13}}\] |
Solubility of \[Ni{{(OH)}_{2}}=2\times {{10}^{-13}}M\] |
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