A) \[\frac{1}{\sqrt{2}n\pi {{d}^{2}}}\]
B) \[\frac{1}{\sqrt{2}{{n}^{2}}\pi {{d}^{2}}}\]
C) \[\frac{1}{\sqrt{2}{{n}^{2}}{{\pi }^{2}}{{d}^{2}}}\]
D) \[\frac{1}{\sqrt{2}n\pi d}\]
Correct Answer: A
Solution :
| [a] According to the formula |
| \[\lambda =\frac{1}{\sqrt{2}n\pi {{d}^{2}}}\] |
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