A) acceleration remains unchanged
B) velocity remains unchanged
C)
speed of the particle remains unchanged D)
direction of the particle remains unchanged
Correct Answer:
C Solution :
Note: If a charged particle moves at \[{{45}^{o}}\] to magnetic field then path of the particle will be a helix whose circular part has radius according to relation \[r=\frac{mv\,\sin \theta }{qB}\].
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