A) depends on v and not on R
B) depends on both R and v
C) is independent of both R and v
D) depends on R and not on v
Correct Answer: C
Solution :
| [c] Key Idea: To move on circular path in a magnetic field, a centripetal force is provided by the magnetic force. |
| When magnetic field is perpendicular to motion of charged particle, then |
| Centripetal force = magnetic force |
| i.e., \[\frac{m{{v}^{2}}}{R}=Bqv\] |
| or \[R=\frac{mv}{Bq}\] |
| Further, time period of the motion |
| \[T=\frac{2\pi R}{v}=\frac{2\pi \left( \frac{mv}{Bq} \right)}{v}\] |
| or \[T=\frac{2\pi m}{Bq}\] |
| It is independent of both R and v. |
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