NEET Physics Magnetic Effects of Current / करंट का चुंबकीय प्रभाव NEET PYQ-Magnetic Effects Of Current

  • question_answer
    A closely wound solenoid of 2000 turns and area of cross-section \[1.5\times {{10}^{-4}}{{m}^{2}}\] carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field \[5\times {{10}^{-2}}T\] making an angle of 30° with the axis of the solenoid. The torque on the solenoid will be                                                                                                       [AIPMT (M) 2010]

    A)  \[3\times {{10}^{-3}}N-m\]     

    B)  \[1.5\times {{10}^{-3}}N-m\]

    C)  \[1.5\times {{10}^{-2}}N-m\]

    D)       \[3\times {{10}^{-2}}N-m\]

    Correct Answer: C

    Solution :

    [c] Given,          \[N=2000,A=1.5\times {{10}^{-4}}{{m}^{2}}\]
    \[i=2.0AB=5\times {{10}^{-2}}T,\]
    and       \[\theta ={{30}^{o}}\]
                Torque  \[\tau =NiBA\sin \theta \]
                 \[=2000\times 2\times 5\times {{10}^{-2}}\times 1.5\times {{10}^{-4}}\times \sin {{30}^{o}}\]
                \[=2000\times 50\times {{10}^{-6}}\times \frac{1}{2}\]
                \[=1.5\times {{10}^{-2}}Nm\]


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