A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) 1
D) 4
Correct Answer: C
Solution :
| [c] For points inside the wire |
| \[B=\frac{{{\mu }_{0}}Ir}{2\pi {{R}^{2}}}(r\le R)\] |
| For points outside the wire |
| \[B=\frac{{{\mu }_{0}}I}{2\pi R}(r\ge R)\] |
| according to the question |
| \[\frac{B}{B'}=\frac{\frac{{{\mu }_{0}}I(a/2)}{2\pi {{a}^{2}}}}{\frac{{{\mu }_{0}}I}{2\pi (2a)}}=1:1\] |
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