A) \[0.2\text{ }T\]
B) \[2\times {{10}^{-4}}T~\]
C) \[6.28\times {{10}^{-4}}T\]
D) \[9.8\times {{10}^{-4}}T\]
Correct Answer: C
Solution :
| [c] At the centre of circular coil carrying current, the magnetic field is, |
| \[B=\frac{{{\mu }_{0}}Ni}{2r}\] |
| Where N = number of turns in the coil |
| i = current flowing |
| r = radius of the coil |
| Given, \[N=1000,\text{ }i=0.1\text{ }A,\text{ }r=0.1\text{ }m\] |
| Substituting the values, we have |
| \[B=\frac{4\pi \times {{10}^{-7}}\times 1000\times 0.1}{2\times 0.1}\] |
| \[=2\pi \times {{10}^{-4}}=6.28\times {{10}^{-4}}\,tesla\] |
| Note: Tesla is the unit of B is SI system. In the same system the unit of B is also \[Wb/{{m}^{2}}.\] In the CGS system, its unit is gauss. |
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