A) \[2\sqrt{3}\,J\]
B) \[3\,J\]
C) \[\sqrt{3}\,J\]
D) \[\frac{3}{2}\,\,J\]
Correct Answer: B
Solution :
| [b] In this case, work done |
| \[W=MB(\cos {{\theta }_{1}}-\cos {{\theta }_{2}})\] |
| \[=MB(\cos {{0}^{o}}-\cos {{60}^{o}})\] |
| \[=MB\left( 1-\frac{1}{2} \right)=\frac{MB}{2}\] |
| \[MB\,=\,2\sqrt{3}\,J\] \[(\because \text{given}\,\,W=\sqrt{3}\,J)\] |
| \[\tau \,=\,MB\,\sin \,{{60}^{o}}=\,(2\sqrt{3})\left( \frac{\sqrt{3}}{2} \right)J\,=\,3\,J\] |
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