A) \[[M{{L}^{2}}{{T}^{-2}}]\]
B) \[[M{{L}^{-1}}{{T}^{-2}}]\]
C) \[[M{{L}^{-2}}{{T}^{-1}}]\]
D) \[[ML{{T}^{-1}}]\]
Correct Answer: A
Solution :
Dimensions of \[{{\varepsilon }_{0}}=[{{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}]\] |
Dimensions of \[E=[ML{{T}^{-3}}{{A}^{-1}}]\] |
\[\therefore \] Dimensions of \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=[{{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}]\]\[\times [{{M}^{2}}{{L}^{2}}{{T}^{-6}}{{A}^{-2}}]\] |
\[=[M{{L}^{-1}}{{T}^{-3}}]\] |
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