A) 68%
B) 41%
C) 200%
D) 100%
Correct Answer: B
Solution :
Velocity \[v=\sqrt{2gh}\] ... (i) |
and momentum\[p=\text{ }mv\] ... (ii) |
From Eqs. (i) and (ii), we have |
\[p\propto \sqrt{h}\] |
Here \[\frac{{{p}_{2}}}{{{p}_{1}}}=\sqrt{\frac{{{h}_{2}}}{{{h}_{1}}}}\] |
\[\therefore \] \[\frac{{{p}_{2}}}{{{p}_{1}}}=\sqrt{\frac{2h}{h}}=\sqrt{2}\] |
\[{{p}_{2}}=1.414{{p}_{1}}\] |
% change \[=\frac{{{p}_{2}}-{{p}_{1}}}{{{p}_{1}}}\times 100=41%\] |
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