NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    A block B is pushed momentarily along a horizontal surface with an initial velocity v. If \[\mu \] is the coefficient of sliding friction between B and the surface, blocks will come to rest after a time: [AIPMT (S) 2007]

    A) \[\frac{v}{g\mu }\]

    B) \[\frac{g\mu }{v}\]

    C) \[\frac{g}{v}\]

    D) \[\frac{v}{g}\]

    Correct Answer: A

    Solution :

    Block B will come to rest, if force applied to it will vanish due to frictional force acting between block B and surface, i,e.,  force applied = frictional force
                i.e.,       \[\mu mg=ma\]
                or         \[\mu mg=m\left( \frac{v}{t} \right)\]
    or         \[t=\frac{v}{\mu g}\]


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