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NEET Physics NLM, Friction, Circular Motion NEET PYQ-NLM Friction Circular Motion

  • question_answer
    S and is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be                              [AIPMPT (S) 2008]

    A) Mv newton

    B) 2 Mv newton     

    C) \[\frac{Mv}{2}\] newton

    D) zero

    Correct Answer: A

    Solution :

    Force required, \[F=\frac{d(mv)}{dt}\]\[=v\left( \frac{dm}{dt} \right)=vM\] as velocity v is constant, hence \[F=Mv\] newton


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